The solution to the problem is that the tension in the string is and the mass of the second object is 1. Identify the given values Mass of the first object ( Acceleration of the system ( Acceleration due to gravity ( We need to find the tension ( ) and the mass of the second object ( 2. Analyze the forces on the first object
m2⋅g−m2⋅a=Tm sub 2 center dot g minus m sub 2 center dot a equals cap T teen streap
m2⋅(g−a)=Tm sub 2 center dot open paren g minus a close paren equals cap T The solution to the problem is that the
m2=0.610−2.0m sub 2 equals the fraction with numerator 0.6 and denominator 10 minus 2.0 end-fraction m2=0.68.0m sub 2 equals 0.6 over 8.0 end-fraction m2=0.075 kgm sub 2 equals 0.075 kg 🏁 Final Answer The tension in the string is and the mass of the second object is Analyze the forces on the second object Since
T=0.3 kg⋅2.0 m/s2cap T equals 0.3 kg center dot 2.0 m/s squared T=0.6 Ncap T equals 0.6 N 3. Analyze the forces on the second object
Since the first object is resting on a smooth horizontal table, the only horizontal force acting on it is the tension of the string.Using Newton's second law ( ) for the first object: T=m1⋅acap T equals m sub 1 center dot a Substitute the known values: