xn+1=xn+1⌊xn⌋x sub n plus 1 end-sub equals x sub n plus the fraction with numerator 1 and denominator the floor of x sub n end-floor end-fraction
. Eventually, these additions must push the sum to the next integer Selected Problems of the Vietnamese Mathematica...
Utilizing radical axes or harmonic bundles (a Vietnamese specialty). xn+1=xn+1⌊xn⌋x sub n plus 1 end-sub equals x