"It's Propane!" Maxim shouted. The "mystery gas" was the very fuel used in camping stoves. He quickly printed a new label— C3H8cap C sub 3 cap H sub 8
He checked the density. The problem mentioned the relative density of the gas compared to air is approximately
n(C)=n(CO2)=13.2 g44 g/mol=0.3 moln open paren cap C close paren equals n open paren cap C cap O sub 2 close paren equals the fraction with numerator 13.2 g and denominator 44 g/mol end-fraction equals 0.3 mol Since each H2Ocap H sub 2 cap O molecule has two hydrogen atoms: "It's Propane
M=Dair×Mair=1.52×29 g/mol≈44 g/molcap M equals cap D sub a i r end-sub cross cap M sub a i r end-sub equals 1.52 cross 29 g/mol is approximately equal to 44 g/mol The molar mass of C3H8cap C sub 3 cap H sub 8 (Propane) is:
Since all carbon from the hydrocarbon ends up in CO2cap C cap O sub 2 The problem mentioned the relative density of the
—and taped it to the cylinder. Elena Petrovna walked in, saw the calculation on the board, and smiled.
"First," he muttered, "I need to find the amount of substance for Carbon and Hydrogen." It felt like a detective’s manual
Maxim opened his to Exercise 16 . It felt like a detective’s manual. Step 1: Collecting the Clues The problem stated that of an unknown organic gas produced of carbon dioxide ( CO2cap C cap O sub 2 of water ( H2Ocap H sub 2 cap O ) upon combustion. Maxim knew this was his starting point.